Chloroform, CHCI₃, boils at 61.7^oC. If the K_b for chloroform is 3.63^oC/molal, what is the boiling point of a solution of 15.0 kg of CHCl₃ and 0.616 kg of acenaphthalene, C₁₂H₁₀ ?

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62.67

52.2

61.9

62.0

answer is D.

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Detailed Solution

$\begin{array}{l} {ΔT}_{b} = K_{b} \cdot m \Rightarrow 3 .63 \times \frac{0 .616 / 154}{15} \times 1000 \\ T_{b} = 61 .7 + 0 .968 \\ \Rightarrow 62 {.67}^{\circ} C \end{array}$

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