Chlorophyll extracted from the crushed green leaves was dissolved in water to make 2L solution of Mg of concentration 48ppm. The number of atoms of Mg in this solution is $x \times 10^{20}$ atoms. The value of x is (Nearest Integer) (Given : Atomic mass of $Mg is 24 g {mol}^{- 1}; N_{A} = 6.02 \times 10^{23} {mol}^{- 1})$

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answer is 24.

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Detailed Solution

$\begin{array}{l} ppm = \frac{W_{solute}}{Volume of solution (in mL)} \times 10^{6} \\ \Rightarrow \frac{W_{solute}}{2000} \times 10^{6} = 48 \\ \Rightarrow W_{solute} = 48 \times 2 \times 10^{- 3} \end{array}$
$Moles of Mg = \frac{48 \times 2 \times 10^{- 3}}{24} = 4 \times 10^{- 3} mol$
Atoms of $Mg = 4 \times 10^{- 3} \times 6 .022 \times 10^{23} = 24 \times 10^{20}$
So, the value of x is 24.