Choose correct statement : If capacitance increases from zero (0) to infinite ($\infty$)
 

$\text{(a) I=}\frac{\mathrm{V}}{\sqrt{{\mathrm{R}}^2+{\left(\mathrm{\omega L}-\frac{1}{\mathrm{\omega C}}\right)}^2}}$
When C = 0 and I = 0 As C increases, 1/$\mathrm{\omega }$C may become equal to $\mathrm{\omega }$L and current will be maximum. When C increases further, current I decreases but does not become zero. As C →$\infty$ : Actually, if becomes
${\mathrm{V}}_1={\mathrm{IZ}}_1=\mathrm{I}\left(\sqrt{{\mathrm{R}}^2+{\mathrm{\omega }}^2{\mathrm{L}}^2}\right)$
(c) Power factor = $\cos \mathrm{\varphi }=\frac{\mathrm{R}}{\mathrm{Z}}=\frac{\mathrm{R}}{\sqrt{{\mathrm{R}}^2+{\left(\mathrm{\omega L}-\frac{1}{\mathrm{\omega C}}\right)}^2}}$
When C = 0, cos$\mathrm{\varphi }$ = 0
As C increases, power factor increases and becomes I (maximum) when X_L = X_C 
As C increases further, power factor decreases.
(d) V₁ may be = > or <V. 
Hence, all options are correct.