Q.

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A hemophilic man marries a non-hemophilic homozygous woman. What are the chances that their sons will have hemophilia?

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a

100 percent

b

0 percent

c

75 percent

d

50 percent

answer is D.

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Detailed Solution

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The gene for the sex-linked recessive condition hemophilia is located on the X chromosome. 

A man with hemophilia is homozygous recessive (XHXh) for the gene that causes the disorder, while a non-hemophilic homozygous woman is homozygous dominant (XHY) for the same gene.

When they have children, the chance of their sons having hemophilia is zero percent, because the son will inherit an X chromosome from his mother and an X chromosome from his father. Since the mother's X chromosome carries the dominant, non-hemophilic allele, the son will be XHY, which means he will not have hemophilia. This is because the dominant allele will mask the recessive allele.

The chance of their daughters having hemophilia is 50%. This is because their daughters will inherit an X chromosome from their mother and an X chromosome from their father. Since the father is homozygous recessive for the hemophilia allele, he will pass on his XH allele to his daughters. The daughters will be XHXh, which means that they are carriers of the disorder. They will not have the disorder, but they have a 50% chance of passing it on to their children.

Therefore, the likelihood of sons having hemophilia is 0%.

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Choose the correct answer:A hemophilic man marries a non-hemophilic homozygous woman. What are the chances that their sons will have hemophilia?