choose the correct option

Assertion-1 is True reason-2 is True; reason-2 is a correct explanation for Statement-1

Diluted ${\mathrm{AlCl}}_3$ More soluble in ${\mathrm{AlCl}}_3$ is more than hydrous. since anhydrous ${\mathrm{AlCl}}_3$ lacks electrons.

Ethylene's oxygen atom provides a pair of p-orbital electrons to the Al atom, creating a bond.

${\mathrm{AlCl}}_3$ is not an electron-deficient chemical when it is hydrated, but it is when it is anhydrous. Consequently, anhyd. Because either oxygen atom donates a pair of electrons to the empty p-orbital on the Al atom in ${\mathrm{AlCl}}_3$, creating a coordinate bond, ${\mathrm{AlCl}}_3$ is more soluble in diethyl ether. Al is not electron-deficient in hydrated ${\mathrm{AlCl}}_3$ since ${\mathrm{H}}_2\mathrm{O}$ has already given it a pair of electrons.

Hence correct option is A.