Choose the correct option for the following given statements.

(i) Copper sulphate is heated up to 230 temperature and gives copper sulfate

(ii) Copper sulphate reacts with ammonium hydroxide and produces a coordinate compound.

(iii) When Silver nitrate reacts with hydrochloric acid, silver chloride ppt is obtained.

(iv) Reaction of Mercuric chloride with potassium iodide is an example of displacement reaction.

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Only (i), (ii), (iii) are correct

Only (i) and (ii) are correct

All are incorrect.

All are correct

answer is C.

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Detailed Solution

Concept: When copper sulphate is heated up to 230 degrees C temperature, it loses a molecule of water to form anhydrous copper sulphate. The first statement is therefore true.

C u S O 4 . H 2 O → C u S O 4 + H 2 O

When copper sulphate reacts with ammonium hydroxide, it forms a copper complex in which the complex cation has

C u

(II) ion surrounded by four ammonia ligands. As we can see, a coordinate compound is formed as one of the products, which makes this statement also a correct one.

C u S O 4 + 4 N H 4 O H → [C u (N H 3) 4] S O 4 + 4 H 2 O

A white precipitate of silver chloride is produced when silver nitrate and hydrochloric acid interact. Nitric acid is the byproduct. This is also a true statement.

A g N O 3 + H C l → A g C l ↓ + H N O 3

Potassium chloride and mercuric iodide are produced when mercuric chloride and potassium iodide combine. There is an exchange of ions between two reactants and therefore this reaction is an example of a double displacement reaction and not a displacement reaction. Therefore, the last statement given is untrue.

H g C l 2 + 2 K I → H g I 2 + 2 K C l

Hence, the correct answer is option 3.

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