Choose the correct option:Expand: -233

Given: -233We know, the law of exponents,am÷bm=ambm=abmTherefore, -233=(-2)333=(-2)×(-2)×(-2)3×3×3

Choose the correct option:Expand: -233

Given: -233We know, the law of exponents,am÷bm=ambm=abmTherefore, -233=(-2)333=(-2)×(-2)×(-2)3×3×3

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Expand: ${(\frac{- 2}{3})}^{3}$

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$\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{(- 2) \times (- 2) \times (- 2)}{3 \times 3 \times 3}$

$\frac{(- 2) \times (- 2) \times (- 2)}{(- 3) \times (- 3) \times (- 3)}$

$\frac{2 \times 2}{3 \times 3}$

answer is B.

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Detailed Solution

Given: ${(\frac{- 2}{3})}^{3}$

We know, the law of exponents,

$a^{m} \div b^{m} = \frac{a^{m}}{b^{m}} = {(\frac{a}{b})}^{m}$

Therefore, ${(\frac{- 2}{3})}^{3} = \frac{{(- 2)}^{3}}{3^{3}} = \frac{(- 2) \times (- 2) \times (- 2)}{3 \times 3 \times 3}$

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Choose the correct option:
Expand: ${(\frac{- 2}{3})}^{3}$