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For reaction $N_{2} O_{4} (g) ⇌ 2 N O, (g);$ degree of dissociation $(α)$ is $\sqrt{\frac{K_{p}}{4 P + K_{p}}}$ where P is equilibrium pressure

Favourable conditions for formation of graphite are high pressure and low temperature from equilibrium diamond (d=3.5 g/ml) $⇌$ graphite (d=2.3 g/ml); $Δ H = - 1.9 k J / m o l e$

For reaction $C l_{2} (g) + 3 F_{2} (g) ⇌ 2 C l F_{3} (g); Δ H = - 329 k J,$ dissociation of $C l F_{3} (g)$ will be favoured by addition of inert gas at constant pressure

Solubility of gas in liquid increases with increasing of temperature

answer is B, C.

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Detailed Solution

Low pressure and low temperature of favorable for the formation of diamond to graphite solubility of gas in liquid increases with increasing of temperature

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