Choose the correct statement(s) among the following :

1) [FeCl₄]^-
 

[FeCl₄]^- is sp³ hybridised and has tetrahedral geometry with 5 unpaired electrons

2) [Co(en)(NH₃)₂Cl₂]⁺ has three geometrical isomers.

3) [FeCl₄]^-

Number of unpaired electrons (n) = 5 

Spin only magnetic moment  $\begin{array}{r}=\sqrt{n(n+2)}\text{ B.M. }\\ \end{array}$

                                                 $=5.92\mathrm{B}.\mathrm{M}$

${\left[\mathrm{Co}\left(\mathrm{en}\right){\left({\mathrm{NH}}_3\right)}_2{\mathrm{Cl}}_2\right]}^{+}$

Number of unpaired electrons (n) = 0 

Spin only magnetic moment $=\sqrt{n(n+2)}\text{ B.M. }$

                                              = 0

4) ${\left[\mathrm{Co}\left(\mathrm{en}\right){\left({\mathrm{NH}}_3\right)}_2{\mathrm{Cl}}_2\right]}^{+}$

[Co(en)(NH3)₂Cl₂]⁺ is d² sp³ hybridised and has octahedral geometry with 0 unpaired electron