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All group - 16 elements form oxides of general formula $E_{2} O_{3}$ and $E O$

$T e O_{2}$ is an oxidising agent while $S O_{2}$ is reducing agent

The reducing property decreases from $H_{2} S$ to $H_{2} T e$ down the group.

The $O_{3}$ molecule contains 5 lone pair of electrons

answer is B.

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$T e O_{2}$ is oxidizing agent, $S O_{2}$ is reducing nature

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