Choose the incorrect statement about the two circles whose equations are given below:

$x^2+y^2-10x-10y+41=0$  and  $x^2+y^2-16x-10y+80=0$

$x^2+y^2-10x-10y+41=0$         $C_1=\left(5,5\right)$ ,            $r_1=3$     

$x^2+y^2-16x-10y+80=0$          $C_2=\left(8,5\right)$            $r_2=3$  

Distance between centres = 3

Thus both circles pass through the centre of each other have two intersection point and distance between two centres in average of radii of both the circles.