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If we construct a trapezium ABCD where AB||CD, AD = BC = 3.2cm, AB = 6.4 cm and CD = 9.6 cm then the measure ∠B and ∠A are $∠ A = 120 °$ and $∠ B = 60 °$ .

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Detailed Solution

Given that, ABCD is a trapezium also we have,
AB || CD,
AD = BC = 3.2 cm,
AB = 6.4 cm and CD = 9.6 cm.
Now constructing a trapezium ABCD and determining the measure of ∠B and ∠A.
To construct a trapezium ABCD,
Drawing a line DC = 9.6 cm taking D as center, drawing an angle that is equal to 60°. Now, cutting an arc of length 3.2cm cm named that point A.
Drawing a line AB which is equal to CD and taking C as center, cutting an arc B of length 3.2 cm which is parallel to previous parallel line. Then drawing a line BE = 3.2 cm from arc B and joining B to E and C.
So, the measure of ∠A = 120° and ∠B = 60°.
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