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Q.

Choose whether the given statement is true or false.


If two tangents to a parabola y2=4ax meet at an angle of  45°, then the locus of their point of intersection is the curve  y2-4ax=(x+a2).


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a

True

b

False 

answer is A.

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Detailed Solution

We are given the equation of parabola opened towards right as
y2=4ax ......(1)
We know that the equation of any tangent to parabola (1) is given by
y=mx+am.......(2)
 Let (h, k) be the coordinates of the point of intersection of the tangents meeting at 45∘45∘ angle as given in the question. Since (h, k) lies on the tangent line (2) we have;
k=mh+am
hm2-km+a=0
The roots of the above equation say m1,m2 will be the slopes of intersecting tangents. We use the sum of the roots formula and have;
m1+m2=-(-k)h=kh
We use product of the roots formula and have;
m1m2=ah
We use the algebraic identity a+b2-a-b2=4ab
for a=m1,b=m2 to have;
(m1-m2)2=(m1+m2)2-4m1m2
(m1-m2)2=(kh)2-4(ah)
m1-m22=k2-4ahh2
m1-m2=±k2-4ahh
 We know that the angles between two lines θ with slopes m1,m2 is obtained from the equation
tanθ=m1-m21+m1m2
We put the given θ=45° an previously obtained m1m2=ah , m1-m2=±k2-4ahh to have;
tantan 45°=±k2-4ahh1+ah 
We square both side to have;
1=k2-4ah(h+a)2
We replace (h ,k)  by ((x, y) to represent all such points of intersection of tangents y=m1x+am1 , y=m2x+am2 as the locus y2-4ax=(x+a)2
Hence the given statement is proved.
So, the given statement is true.
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