Choose which of the following is odd one out:

(i)- Camphor, Ammonium Chloride, Naphthalene balls, Sugar

(ii)- Turmeric, Methyl Orange, Rose petals, Beetroot

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Methyl orange is the odd one as it is not an natural indicator

Camphor is the odd one as it is not a natural indicator.

Naphthalene balls is the odd one as it is not a natural indicator.

None of these

answer is A.

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Detailed Solution

Concept- Volatility of compounds Camphor is a translucent waxy organic chemical. If left open, it quickly evaporates (converts to a gaseous state). It's a very flammable substance.
Ammonium chloride is an inorganic salt used in the qualitative evaluation of salts. It decomposes quickly into ammonia and hydrochloric acid.
Naphthalene balls are a natural substance that quickly devolves into a vapour state.
(i) Sugar is a carbonyl organic molecule with a sweet flavour. It is non-volatile in nature i.e. It is not immediately transformed to a gaseous state.
(ii) Methyl orange
Turmeric in basic media, it turns red, whereas in an acidic medium, it turns yellow and is a natural indicator.
Rose petal pigments are used as a natural indicator. In an acidic media, it produces a dark red colour, whereas in a basic medium, it produces a reddish green colour.
Beetroot is also a natural indicator and it contains anthocyanin. In an acidic medium, it turns red, while in a basic condition, it turns blue.
Methyl orange is a chemical that has been synthesised. In an acidic medium, it turns red, while in a basic medium, it turns yellow.
Out of all, only methyl orange is a synthetic indicator whether rest are natural indicators.
Thus, methyl orange is the odd one out.
Hence, the correct option is 1.

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