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Cis-platin $[Pt {({NH}_{3})}_{2} {Cl}_{2}]$ , a compound used in cancer treatment is prepared by reaction of ammonia with potassium tetrachloro platinate.
$K_{2} {PtCl}_{4} + 2 {NH}_{3} ⟶ 2 KCl + Pt {({NH}_{3})}_{2} {Cl}_{2}$
(P) How many grams of cis-platin are formed from 41.5 g $K_{2} {PtCl}_{4}$ and $34 g m {NH}_{3}$ if the reaction takes place in 90 % yield? [ Ans = (x)]
(Q) What is the maximum mass of $KCl$ which can be produced if initially total 9 moles of reactant are taken. Assuming 100 % reactions. [Ans (y)]
[Write the value of $(x + y), (Pt = 195)$ ]

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answer is 474.

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Detailed Solution

We have given the value

$(P) \frac{41.5}{415} \times 0.9 \times 300 = 27.0 g = x$

$(Q) 3 \times 2 \times 74.5 = 447 = y$

we get

$x + y = 474$

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