$C l_{2}$ disproportionates into $C l^{-} a n d C l O_{3}^{-}$ in alkali. What can we conclude ?

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$\frac{5}{6}$ th parts of chlorine is reduced

Eq. wt of oxidized chlorine is 7.1

Eq. wt of reduced chlorine is 35.5

Equal no of equivalents of $C l_{2}$ involved in oxidation and reduction half reactions

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Detailed Solution

$3 C l_{2} + 6 O H^{-} \to 5 C l^{-} + C l O_{3}^{-} + 3 H_{2} O$

$\frac{5^{t h}}{6}$ parts (5 chlorine out of 6) of chlorine is reduced

Eq. wt of oxidized chlorine is 7.1

Eq. wt of reduced chlorine is 35.5

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