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$\dot{Cl} + {CH}_{4} \to A + B$
A and B in the above atmospheric reaction step are

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$C_{2} H_{6} and HCl$

$C_{2} H_{6} and {Cl}_{2}$

$\dot{C} H_{3} and HCl$

$\overset{∙}{C} {HCl}_{2} + H_{2}$

answer is C.

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${CH}_{4} + \dot{Cl} \to {C \dot{H}}_{3} + HCl$

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