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$C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g) Δ H = - 270 K J$ . Find $Δ S_{t o t a l}$ of the reaction at 300 K if $S_{C O_{2}} = 215 J K^{- 1} m o l^{- 1}; S_{C O} = 200 J K^{- 1} m o l^{- 1}$ and $S_{O_{2}} = 210 J K^{- 1} m o l^{- 1}$ .

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760 J

810 J

1200 J

575 J

answer is B.

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Detailed Solution

$C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g) Δ H = - 270 K J$

$Δ S_{s y s t e m} > S_{C O_{2}} - [S_{C O} + \frac{1}{2} S O_{2}]$

$215 - [200 + \frac{210}{2}] = - 90 J K^{- 1}$

$Δ S_{S u r r o u n d i n g} = \frac{- Δ H}{T} = \frac{270 \times 1000}{300} = 900 J o u l e s$

$Δ S_{T o t a l} = Δ S_{S y s t e m} + Δ S_{S u r r o u n d i n g s} = - 90 + 900 = 810 J K^{- 1}$

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