CO₂ has the same geometry as 

A) ${\mathrm{HgCl}}_2$ B) NO₂ C) ${\mathrm{SnCl}}_4$ D) ${\mathrm{C}}_2{\mathrm{H}}_2$

O = C = O sp-hybrid orbitals ; linear 

${\mathrm{HgCl}}_2\to \mathrm{Cl}-\mathrm{Hg}-\mathrm{Cl};\mathrm{\mu }=0,\text{ linear }$
 

$\mathrm{\mu }=0,{\mathrm{sp}}^3$ hybridisation trigonal planar $\mathrm{H}-\mathrm{C}\equiv \mathrm{CH};\mathrm{\mu }=0,\text{ linear }$