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COCI₂ gas dissociates according to the equation, ${COCl}_{2} (g) ⇌ CO (g) + {Cl}_{2} (g)$ when heated to 700 K the density of the gas mixture at 1.16atm and at equilibrium is 1.16 g/liter. The degree of dissociation of ${COCl}_{2} at 700 K is.$

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0.28

0.50

0.72

0.42

answer is C.

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Detailed Solution

$M_{O} (observed molar mass) = \frac{dRT}{P} = 57.47 M_{T} (Theoritical molar mass) = 99 α = \frac{M_{T} - M_{o}}{(n - 1) M_{o}} = \frac{99 - 57.47}{57.47} = 0.72$

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