Q.

Coefficient of x10 in (1+2x)21+(1+2x)22++(1+2x)30 is

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a

 31C11

b

210 31C1121C11

c

29 31C1121C11

d

210 30C1121C11

answer is A.

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Detailed Solution

Coefficient of x10 in

(1+2x)21+(1+2x)22++(1+2x)30⇒=(1+2x)21(1+2x)1012xCosx10 in (1+2x)31(1+2x)212xcoefficient of x11 in 12(1+2x)31(1+2x)21⇒=12 31C1121121C11211= 31C1121C11210

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