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Q.

Coefficient of xn in x(x1)2(x2) is Cn then limnCnn=

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Detailed Solution

x(x1)2(x2)=2x11(x1)2+2x2

=2[1x]1[1x]21x21

=21+x+x2++xn+1+2x++(n+1)xn..

+1+x2+.+x2n+

 Coefficient of xn=Cn

=2(n+1)12n=1n12n

LtnCnn=1

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