Coefficients of MnO^-_4,C₂O^2-₄ and H⁺ in the balanced reaction,

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2, 3 and 8

2, 5 and 8

2, 3 and 16

2, 5 and 16

answer is D.

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Detailed Solution

$large MnO_4^ - ; + ;{C_2}O_4^{ - 2}; + ;{H^ + }; to ;M{n^{ + 2}}; + ;C{O_2}; + ;{H_2}O$
$large left. {begin{array}{*{20}{c}} {RHR} \ {MnO_4^ - ; to ;Mn^{ + 2}} \ {Balancing;'O';atom} \ {MnO_4^ - ; to ;M{n^{ + 2}}; + ;4{H_2}O} \ {Balancing;'H';atom;in;acidic;medium} \ {MnO_4^ - ; + ;8{H^ + }; to ;M{n^{ + 2}}; + ;4{H_2}O} \ {Balancing;charges} \ {MnO_4^ - ; + ;8{H^ + }; + ;5bar e; to ;M{n^{ + 2}}; + ;4{H_2}O} end{array}} right|begin{array}{*{20}{c}} {OHR} \ {C_2O_4^{-2}rightarrow CO_2 } \ {Balancing;'C';atom} \ {C_2O_4^{-2} to ;2CO_2} \ {Balancing;the;charge} \ {C_2O_4^{-2}rightarrow 2CO_2;+ ;2bar e} end{array}$
$large begin{array}{*{20}{c}} {(RHR) times 2;;;;;;;;;;;;MnO_4^ - ; + 16{H^ + }; + ;10bar e; to ;2M{n^{ + 2}}; + ;8{H_2}O;;;;;;;;;;;;;} \ {(OHR) times 5;;;;;;;;;;;;;;;;;;;;;;;;;;;;;5{C_2}O_4^{ - 2}; to ;10C{O_2}; + 10bar e;;;;;;;;;;;;;;;;;;} \ {overline {underline {Net;reaction;2MnO_4^ - ; + ;5{C_2}O_4^{ - 2}; + ;16{H^ + }; to ;2M{n^{ + 2}}; + ;10C{O_2}; + ;8{H_2}O} } } end{array}$