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Q.

 Column - I
(Moles of AgCl per mole of compound)
 Column - II
(Secondary valencies)
p)PtCl22NH3zeroi)2
q)CoCl34NH41ii)3
r)PtCl24NH32iii)6
s)CrCl36NH33iv)4
 pqrs
1iiiiiiiv
2iiiiviii
3iviiiiiii
4iviiiiviii

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a

2

b

1

c

3

d

4

answer is D.

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Detailed Solution

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(p) PtCl22NH3zero: i.e. no ions are ionized, secondary valence=4

(q) CoCl34NH31  : one 'Cl' satisfies primary valence, secondary valence=6

(r) PtCl24NH32 : Two 'Cl' s satisfies primary valence, secondary valence=4

(s) CrCl36NH33 ; Three 'Cl' s satisfies primary valence, secondary valence=6

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