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Column - I
(Reaction)
Column – II
(Mechanism)
I $C_{2} H_{5} B r \to_{}^{a q . K O H}$ $C_{2} H_{5} O H$ A
Free radical substitution
II $C_{6} H_{6} \to_{d a r k}^{B r_{2} / F e}$ $C_{6} H_{5} B r$ B
Nucleophilic substitution
III $C_{6} H_{5} - C H_{3} \to_{773 K}^{B r_{2}}$ $C_{6} H_{5} C H_{2} B r$ C
Electrophilic substitution
Correct match of Column - I and Column - II is

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I - C , II - A , III - B

I - B , II - C , III - A

I - A , II - B , III - C

I - A , II - C , III - B

answer is B.

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Detailed Solution

Alkanes can undergo free-radical substitution in which a hydrogen atom gets substituted by a halogen (chlorine/bromine) Since alkanes are very unreactive, ultraviolet light (sunlight) is needed for this substitution reaction to occur.

Nucleophilic substitution reaction is a type of organic reaction where one nucleophile is replaced by others.

Electrophilic aromatic substitution reactions are organic reactions wherein an electrophile replaces an atom which is attached to an aromatic ring.

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