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Q.

Column - I

Complex

Column - II

Hybidisation

a)Ni(CO)4p)sp3
b)Ni(CN)42q)dsp2
c)Fe(CN)64-r)sp3d2
d)MnF64s)d2sp3

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a

a-r, b-q, c-s, d-r 

b

 a-r, b-p, c-s, d-q 

c

a-p, b-q, c-s, d-r

d

a-s, b-p, c-q, d-r

answer is A.

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Detailed Solution

detailed_solution_thumbnail

In Ni(CO)4 , Ni has zero oxidation state and its outer electronic configuration is 3d84s2. As CO is a strong ligand, so all 3d and 4s electrons are paired and complex shows sp3 hybridization.

In Ni(CN)42-, Ni has +2 oxidation state and its outer electronic configuration is 3d84s0. As CN is a strong ligand so all 3d electrons are paired and complex shows dsp2 hybridization.

In Fe(CN)64-, Fe has +2 oxidation state and its outer electronic configuration is 3d64s0. As CN is a strong ligand, so all 3d electrons are paired and complex shows d2sp3 hybridization.

In MnF64-, Mn has +2 oxidation state and its outer electronic configuration is 3d54s0. As F is a weak ligand, so 3d electrons remain unpaired and complex shows sp3d2 hybridization.

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