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Column -1 few physical quantities and column –II their dimensional formulae given
Column-I Column-II
P) Pressure gradient M) $[M^{1} L^{2} T^{- 2}]$
Q) Energy density N) $[M^{1} L^{1} T^{- 1}]$
R) Torque O) $[M^{1} L^{- 2} T^{- 2}]$
S) Impulse T) $[M^{1} L^{- 1} T^{- 2}]$

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$P - O, Q - M, R - N S - T$

$P - O, Q - T, R - M, S - N$

$P - M, Q - T, R - N, S - O$

$P - M, Q - O, R - N, S - T$

answer is B.

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Detailed Solution

$\frac{d p}{d x} = \frac{M L^{- 1} T^{- 2}}{L} = [M^{1} L^{- 2} T^{- 2}]$

$\frac{d U}{d v} = \frac{M L^{2} T^{- 2}}{L^{3}} = [M^{1} L^{- 1} T^{- 2}]$

Torque = $F \times d i s \tan c e = [M L T^{- 2}] \times [L] = [M^{1} L^{2} T^{- 2}]$

Impulse = $F \times t i m e = [M L T^{- 2}] \times [T] = [M^{1} L^{1} T^{- 1}]$

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