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Q.

 Column -I Column -II
aThe maximum value of {cos(2A+θ)+cos(2B+θ)} is
(where A, B are constants)
p2sin (A + B)
bThe maximum value of {cos2A+cos2B} is
(where (A + B) is constant and A,B(0,π/2))
q2sec (A + B)
cThe minimum value of {sec2A+sec2B} is 
(where (A + B) is constant and A,B(0,π/4))
r2cos (A + B)
dThe minimum value of {tanθ+cotθ2cos2(A+B)} is
(where A, B are constants and θ(0,π/2))
s2cos (A – B)

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a

a-q,b-r,c-s,d-p

b

a-q,b-s,c-r,d-p

c

a-s,b-r,c-q,d-p

d

a-p,b-r,c-s,d-q

answer is A.

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Detailed Solution

a)
{cos(2A+θ)+cos(2B+θ)}=2cos(AB)cos(A+B+θ)
Maximum value is 2cos(A–B) when cos(A+B+θ)=1
b)
{cos2A+cos2B}=2cos(A+B)cos(AB)
Maximum value is 2cos(A–B) when cos(A+B) =1

c)For y=secx,x(0,π/2) , tangent drawn to it at
any point lies completely below the graph of y=secx;
thus, sec2A+sec2B2sec(A+B)
or sec2A+sec2Bsec(A+B)
Hence, the minimum value is 2sec(A+B).
d)
{tanθ+cotθ2cos2(A+B)}=(tanθcotθ)2+22cos2(A+B)=(tanθcotθ)2+4sin2(A+B)
Minimum value occurs when tanθ=cotθ and
minimum value is 4sin2(A+B)=2sin(A+B)

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