Column-I (aqueous solution)		Column-II ('property' among the list A)
A)	$0.1{\mathrm{mK}}_4\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right](\mathrm{\alpha }=1)$	p)	Highest vapour pressure of solution
B)	$0.2\mathrm{m}\left[{\mathrm{K}}_4\left[\mathrm{Hg}\left(\mathrm{CN}{)}_2\mathrm{Fe}\right(\mathrm{CN}{)}_6\right]\right.$	q)	Least colligative property
C)	1m glucose	r)	Highest boiling point
D)	$0.5\mathrm{m}{\mathrm{MgCl}}_2(\mathrm{\alpha }=0.75)$	s)	Highest Vant Hoff factor

	A	B	C	D
1)	s	rs	pq	r
2)	rs	pq	r	s
3)	r	rs	pq	s
4)	pq	s	rs	r

$\text{ A) For }{\mathrm{K}}_4\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]\mathrm{n}=5,\mathrm{\alpha }=1\text{; }$
$\mathrm{i}=(\mathrm{n}-1)\mathrm{\alpha }+1=(5-1)\times 1+1=5$ it has highest vant Hoff factor
$\text{ B) For }{\mathrm{K}}_4\left[\mathrm{Hg}\left(\mathrm{CN}{)}_2\mathrm{Fe}\right(\mathrm{CN}{)}_6\right]\mathrm{n}=5,\mathrm{\alpha }=1\text{; }$
So $\mathrm{i}=1+(\mathrm{n}-1)\mathrm{\alpha }=5$ it has highest vant Hoff factor. It has more boiling point than that of $0.1{\mathrm{mK}}_4\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]$ solution
$\text{ C) for glucose solution, }\mathrm{\alpha }=0,\therefore \mathrm{i}=1$
It has least colligative property and highest vapour pressure.
$\text{ D) For }{\mathrm{MgCl}}_2\text{ solution }\mathrm{\alpha }=0.75,\mathrm{n}=3$
$\therefore \mathrm{i}=1+(\mathrm{n}-1)\mathrm{\alpha }=1+(3-1)\times 0.75=2.5\text{ effective }$molality (EM) is $\Rightarrow 0.5\times 2.5=1.25\mathrm{m}\text{.}$ Em is more than others. So it has highest boiling point.