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Q.

 COLUMN-I COLUMN-II
aThe value of (4+sec20°cosec20°)2 isp1
bThe minimum value of 1+cos2x+8sin2x2sin2x,x(0,π/2), is
 
q2
cThe value of 8sin40°.sin50°.tan10°cos80° isr3
dIf cos5AcosA+sin5AsinA=a+bcos4A then a2/b iss4

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a

ap,bq,cs,dr

b

as,bq,cr,dp

c

ar,bq,cs,dp

d

ar,bp,cs,dq

answer is D.

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Detailed Solution

A) [4+sec20cosec20]2=[sin20cos20(4cos20+1)]2  
=[2sin40+sin20cos20]2=(2sin60cos20cos20)2=3 
B) f(x)=2cos2x+8sin2x2sin2x,f(x)>0  
=cotx+4tanx2=(cotx2tanx)22+2 
f(x)min=2 
C) 8sin40°sin50°tan10°cos80°=4(2sin50sin40)sin10cos10sin10=4  
D) 2sin6Asin2A=2sin3(2A)sin2A=2(34sin22A)  
2sin6Asin2A=2sin3(2A)sin2A=2(34sin22A)a2b=1  

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