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Q.

 Column – I Column – II
i)

Number of arrangements of the letters of

the word ENGINEER so that all vowels are

together but   all E’s are not together

p)22
ii)

Number of ways of arrangements

of the letters of the word ELEVEN so that no two

vowels are together and no two consonants are

together is K than 10K equals

q)23
iii)

Number of ways of keeping 5 letters in 5

addressed envelopes such that no letter goes to its

own envelope is P then P is divisible by

r)5!
iv)

Number of 6 digit numbers greater than 123000

using 1,2,2,3,3,3 is

s)59
  t)12

The correct option is   

see full answer

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a

IR,IIT,IIIP,IVS

b

IS,IIP,IIIQ,IVR

c

IP,IIS,IIIR,IVT

d

IT,IIR,IIIS,IVP

answer is A.

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Detailed Solution

I) ENGINEER

   vowels are E,E,E,I and consonants are N,N,G,R

   required number of ways =5!2!×4!3!5!2!×2=120=5!

II) Required number of ways ELEVEN

LVNconsonantsEEEvowels3!+3!=12

III) number of dearrangements

=5!111!+12!13!+14!15!

=6020+51=44 is divisible by 22

IV) Number of 6 digit numbers

=3!2!+3!2!+3!2!+5!2!2!+513!

=3+3+3+330+20=59

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