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Q.

 

 Column I (Equation) Column II (number of Solutions)
Ax3+x2+4x+2sinx=0  in0x2πP4
Bsinexcosex=2x2+2x2Q1
Csin2x+cos4x=2R2
D30|sinx|=x  in  0x2πS0

   

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a

AR,BQ,CR,DP

b

AS,BQ,CS,DP

c

AP,BQ,CS,DP

d

AQ,BS,CS,DP

answer is A.

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Detailed Solution

A) x3+(x+2)2+2sinx=4  clearly x = 0 satisfy
 0<xπ,   x3+x+22+2sinx>4π<x2π,  x3+(x+2)2+2sinx>27+252
x = 0 is only solution
B)  12sin2ex=2x+2x4    sin(2ex)1sin(2ex)=1  x=0  ,not  true
C) sin2x+cos4x=2sin2x=1,cos4x=1,  nosolution
D) y=|sinx|  y=x300x2π   4 points of intersection

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