Column – I (salt) Column – II $(K_{s p})$
A) Mercurous Iodide P) $108 S^{5}$
B) Aluminium phosphate Q) $4 S^{3}$
C) Calcium phosphate R) $S^{2}$
D) Zirconium phosphate S) $6912 S^{7}$

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$A - Q; B - R; C - P; D - S$

$A - Q; B - S; C - P; D - P$

$A - P; B - R; C - Q; D - S$

$A - R; B - P; C - S; D - Q$

answer is A.

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Detailed Solution

$H g_{2} I_{2} \to H g_{2}^{+ 2} + 2 I^{-} K_{s p} = 4 S^{3} A l (P O_{4}) \to A l^{+ 3} + P O_{4}^{- 3} K_{s p} = S^{2} C a_{3} {(P O_{4})}_{2} \to 3 C a^{+ 2} + 2 P O_{4}^{- 3} K_{s p} = 108 S^{5} Z r_{3} {(P O_{4})}_{4}^{} \to 3 Z r^{+ 4} + 4 P {O_{4}}^{- 3} K_{s p} = 6912 S^{7}$

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