Column-I shows a situation for placing an object and column-II marks corresponding properties of image. Match the columns
Column – I Column – II
(A) Virtual object kept in concave mirror (P) Virtual image is formed
(B) Virtual object between pole and focus of concave lens, kept in air (Q) Real image is formed
(C) Real object kept in between pole and focus of convex lens immersed in medium of larger refractive index the material of lens (R) Enlarged image is formed
(D) Virtual object kept beyond centre of curvature in convex mirror (S) Diminished image is formed
(T) Virtual and Inverted image is formed

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$A \to (Q, T); B \to (Q, R); C \to (P, S); D \to (P, S)$

$A \to (Q, S); B \to (Q, R); C \to (P, S); D \to (P, S)$

$A \to (P, S); B \to (Q, S); C \to (P, T); D \to (P, R)$

$A \to (Q, S); B \to (Q, R); C \to (P, T); D \to (P, R)$

answer is B.

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Detailed Solution

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$ for lens
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ for mirror

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Column – I		Column – II
(A)	Virtual object kept in concave mirror	(P)	Virtual image is formed
(B)	Virtual object between pole and focus of concave lens, kept in air	(Q)	Real image is formed
(C)	Real object kept in between pole and focus of convex lens immersed in medium of larger refractive index the material of lens	(R)	Enlarged image is formed
(D)	Virtual object kept beyond centre of curvature in convex mirror	(S)	Diminished image is formed
		(T)	Virtual and Inverted image is formed