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Q.

Column-I ( solute)

Column-II ( vant half factor, i)

(A)

$A l C l_{3} I f α = 0.8$

(P)

$i = 3.4$

(B)

$B a C l_{2} i f α = 0.9$

(Q)

$i = 2.8$

(C)

$N a_{3} P O_{4} i f α = 0.9$

(R)

$i = 3.8$

(D)

$K_{4} [F e {(C N)}_{6}] i f α = 0.7$

(S)

$i = 3.7$

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a

$A \to P; B \to Q; C \to S; D \to R$

b

$A \to R; B \to S; C \to P; D \to Q$

c

$A \to Q; B \to P; C \to S; D \to R$

d

$A \to P; B \to Q; C \to R; D \to S$

answer is A.

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Detailed Solution

$i = 1 - α + n α$

For $A l C l_{3}; i = 1 - 0.8 + 4 \times 0.8 = 0.2 + 3.2 = 3.4$

For $B a C l_{2}; i = 1 - 0.9 + 3 \times 0.9 = 2.8$

For $N a_{3} P O_{4}; i = 1 - 0.9 + 4 \times 0.9 = 3.7$

For $K_{4} [F e {(C N)}_{6}]; i = 1 - 0.7 + 5 \times 0.7 = 3.8$

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Column-I ( solute) Column-II ( vant half factor, i) (A) AlCl3 If α=0.8 (P) i=3.4 (B) BaCl2 ifα=0.9 (Q) i=2.8 (C) Na3PO4 if α=0.9 (R) i=3.8 (D) K4[Fe(CN)6] if α=0.7 (S) i=3.7