Column-I Column-II
(a) Gypsum (p) ${CaSO}_{4} \cdot \frac{1}{2} H_{2} O$
(b) Plaster of Paris (q) $2 {CaSO}_{4} \cdot H_{2} O$
(c) Dead burnt plaster (r) ${CaSO}_{4} \cdot 2 H_{2} O$
(d) Milk of lime (s) ${CaSO}_{4}$
(t) $Ca (OH)_{2}$

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( a- s ); ( b - p, r ); ( c -p ): ( d - t)

( a - r ); ( b - p, q ); ( c - s ): ( d - t)

( a- q ); ( b - s, q ); ( c - p ): ( d - r)

( a-t ); ( b - s, p ); ( c - r ): ( d -q)

answer is A.

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Detailed Solution

The chemical formula of Gypsum is ${CaSO}_{4} \cdot 2 H_{2} O$ .

The chemical formula of Plaster of Paris is ${CaSO}_{4} \cdot \frac{1}{2} H_{2} O$ & $2 {CaSO}_{4} \cdot H_{2} O$

The chemical formula of Dead burnt plaster is ${CaSO}_{4}$ .

The chemical formula of Milk of lime is $Ca (OH)_{2}$ .

Hence ( a - r ); ( b - p, q ); ( c - s ): ( d - t) is correct.

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