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Column I Column II
(a) ${PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g)$ (i) $K_{p} < K_{c}$
(b) $H_{2} (g) + I_{2} (g) ⇌ 2 HI (g)$ (ii) $K_{p} > K_{c}$
(c) $N_{2} (g) + 3 H_{2} (g) ⇌ 2 {NH}_{3} (g)$ (iii) $K_{p} = K_{c}$
Correct match is
(a) (b) (c)
1 i ii iii
2 i iii ii
3 ii iii i
4 iii i ii

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answer is C.

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Detailed Solution

$(a) Δn = 2 - 1 = 1; K_{p} > K_{c} (b) Δn = 2 - 2 = 0; K_{p} = K_{c} (c) Δn = 2 - 4 = - 2; K_{p} < K_{c}$

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