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Column-I Column-II Column-II
A)H-atom P) Radius of 2nd orbit is i) Energy of the 1^st excited state is -13.6ev
B) ion Q) Energy of the 4^th orbit is =-13.6ev ii) Radius of the 2^nd orbit is
C) ion R) Radius of the 3^rd orbit is iii) Velocity 1^st energy level is cm/sec
D) ion S)Velocity of e^- is the first orbit is cm/sec iv) Velocity of the in the 3^rd orbit is cm/sec
For H-atom, the correct combination is

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(A) (S) (ii)

(A) (S) (iv)

(A) (P) (iv)

(A) (Q) (iv)

answer is A.

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Detailed Solution

$TE = - 13 .6 \times \frac{z^{2}}{n^{2}} eV = - 13.6 \times \frac{1^{2}}{1^{2}} eV = - 13.6 eV$
$V = 2 .188 \times 10^{6} \times \frac{z}{n} m / \sec = 2 .188 \times 10^{6} \times \frac{1}{1} cm / \sec = 2.188 \times 10^{6} cm / \sec$

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