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Q.

Column-IColumn-IIColumn-II
A)H-atomP) Radius of 2nd orbit is i) Energy of the 1st excited state is -13.6ev
B) ionQ) Energy of the 4th orbit is  =-13.6evii) Radius of the 2nd orbit is 
C)  ionR) Radius of the 3rd orbit is iii) Velocity 1st energy level is cm/sec
D) ionS)Velocity of  e- is the first orbit is  cm/seciv) Velocity of the in the 3rd orbit is cm/sec

For H-atom, the correct combination is

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a

(A) (S) (ii)

b

(A) (S) (iv)

c

(A) (P) (iv)

d

(A) (Q) (iv)

answer is A.

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Detailed Solution

TE=13.6×z2n2eV =-13.6×1212eV =-13.6 eV
V=2.188×106×znm/sec=2.188×106×11cm/sec =2.188×106 cm/sec

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