column-I column-II(I)QC > KC(a)Forward reaction is favoured(II)QC < KC(b)Both forward and backward reactions are favoured(III)QC = KC(c)Backward reaction is favouredCorrect match is

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	column-I		column-II
(I)	$Q_{C} > K_{C}$	(a)	Forward reaction is favoured
(II)	$Q_{C} < K_{C}$	(b)	Both forward and backward reactions are favoured
(III)	$Q_{C} = K_{C}$	(c)	Backward reaction is favoured

Correct match is

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I-c, II-a, III-b

I-a, II-b, III-c

I-b, II-a, III-c

I-b, II-c, III-a

answer is C.

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Detailed Solution

$Q_{c} = \frac{[P]}{[R]}; Q_{c} decreases, [P] decreases and if Q_{c} increases, [P] increases$

$Q_{C} > K_{C}$ ; $Q_{C}$ must decrease and become equal to $K_{C}$ thus backward reaction is favoured.

$Q_{C} < K_{C}$ ; $Q_{C}$ must increase and become equal to $K_{C}$ thus forward reaction is favoured.

$Q_{C} = K_{C}$ ; Both forward & backward reactions are favoured.

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