Column (I)
Species
Column (II)
Bond order
(p) ${Li}_{2}$ (i) 2
(q) $C_{2}$ $(i i) 0$
(r) $N_{2}$ $(i i i) 1$
(s) ${He}_{2}$ (iv) 3

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$(p) \overset{}{\to} i; (q) \overset{}{\to} ii; (r) \overset{}{\to} iii; (s) \overset{}{\to} iv$

$(p) \overset{}{\to} iii; (q) \overset{}{\to} i; (r) \overset{}{\to} iv; (s) \overset{}{\to} ii$

$(p) \overset{}{\to} i; (q) \overset{}{\to} i i i; (r) \overset{}{\to} ii; (s) \overset{}{\to} iv$

$(p) \overset{}{\to} iii; (q) \overset{}{\to} i; (r) \overset{}{\to} ii; (s) \overset{}{\to} iv$

answer is B.

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Detailed Solution

$Species - Bond order {Li}_{2} - 1 σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2}; B . O = N_{b} - N_{a} / 2 \Rightarrow 4 - 2 / 2 = 1 C_{2} - 2 σ 1 s^{2} σ^{*} s^{2} σ 2 s^{2} σ^{*} 2 s^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2}; B . O = 8 - 4 / 2 = 2 N_{2} - 3 σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2} σ^{*} 2 s^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} σ 2 p_{z}^{2}; B . O = 10 - 4 / 2 = 3 {He}_{2} - 0 σ 1 s^{2} σ^{*} 1 s^{2}; B . O = 2 - 2 / 2 = 0$