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Q.

Combustion of glucose takes place according to the equation C6H12O6+6O2→6CO2+6H2O;ΔH=−72  kcal/mol.

How much energy will be released by the combustion of 1.6 g of glucose (Molecular mass of glucose = 180  g/mol ) ?

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a

0.064 k cal

b

6.4 k cal

c

64 k cal

d

0.64 k cal

answer is B.

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Detailed Solution

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Combustion of glucose takes place according to the equations C6H12O6+6O2→6CO2+6H2O;ΔH=−72  kcal

ΔH per 1.6g=72×1.6180=0.64  kcal

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