Combustion of sucrose is used by aerobic organisms for providing energy for the life sustaining process. If all the capturing energy from the reaction is done through electrical process ( non P-V work) then calculate maximum available energy which can be captured by combustion of 34.2gm of sucrose. Given $Δ Η_{c o m b u s t i o n} (s u c r o s e) = - 6000 k J m o l^{- 1}, Δ S_{c o m b u s t i o n} = 180 J / K m o l$ and body temperature is 300 K.

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-605.4 kJ

594.6 k Cal

-144.83 k Cal

600 kJ

answer is C, D.

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Detailed Solution

$\begin{array}{l} Δ G = Δ Η - T Δ S = - 6000 - 300 X 0.18 = 6054 k J \\ F o r 34.2 g m S u c r o s e = - 605.4 k . J = - 144.83 k c a l \end{array}$

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