Combustion of sucrose is used by aerobic organisms for providing energy for the life sustaining processes. If all the "capturing" of energy from the reaction is done through electrical process (non PV work) then calculate maximum available energy which can be captured by combustion of 3.42 gm of sucrose

$\text{ Given : }\mathrm{\Delta }{H}_{\text{combustion }}\left(\text{ sucrose }\right)=-6000{\mathrm{kJmol}}^{-1}$ $\mathrm{\Delta }{S}_{\text{combustion }}=180\mathrm{J}/\mathrm{Kmol}$ and the body temperature 300 K.

Express answer in kJ as ab.cd [For example if your answer is 78.42 kJ fill OMR-as 7842]