Comment on the $C - C$ bond length for $C_{2} H_{6}$ and $C_{2} F_{6}$ compounds.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$d_{C - C} (C_{2} H_{6}) > d_{C - C} (C_{2} F_{6})$

$d_{C - C} (C_{2} H_{6}) = d_{C - C} (C_{2} F_{6})$

$d_{C - C} (C_{2} H_{6}) < d_{C - C} (C_{2} F_{6})$

Can't be predicted

answer is A.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Because of electronegative property of molecule $C - C$ bond length of $C_{2} H_{6}$ is greater than $C_{2} F_{6}$ .

So, the correct answer is $d_{C - C} (C_{2} H_{6}) > d_{C - C} (C_{2} F_{6})$ .
Hence, the correct answer is A.

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test