Commercial vinegar is a 5.00% by mass aqueous solution of acetic acid, CH3CO2H(M=60.0) What is the molarity of acetic acid in vinegar?[Density of vinegar =1.00g/mL]

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Commercial vinegar is a $5.00 %$ by mass aqueous solution of acetic acid, ${CH}_{3} {CO}_{2} H (M = 60.0)$ What is the molarity of acetic acid in vinegar?

[Density of vinegar $= 1.00 g / mL$ ]

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0.833 M

3.00 M

1.00 M

1.20 M

answer is A.

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Detailed Solution

It is known that,

$V = \frac{mass of solution}{Density of solution}$

$V = \frac{100.0 g}{1.00 g / mL}$

$\begin{array}{l} V = 100.0 mL \\ V = 0.1 L \end{array}$

The molarity of acetic acid (M) can be found as:

$\begin{array}{l} M = \frac{n}{V} \\ = \frac{0.0833 mol}{0.1 L} \\ = 0.833 M \end{array}$

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