Common salt obtained from Clifton beach contained 60.75% chlorine while 6.40g of a sample of common salt from Khewra mine contained 3.888g of chlorine. State the law illustrated by these chemical combinations.

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Law of reciprocal proportion

Law of multiple proportion

Law of constant composition

None of the above

answer is C.

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Detailed Solution

Concept- According to the law of definite proportion, “ A sample of a pure chemical compound always consists of the same elements combined together in the same definite proportions by mass, regardless of its source."
Now, two common salt samples are given and we need to find the mass of chlorine in 1 g of each sample of salt.
$<math xmlns="http://www.w3.org/1998/Math/MathML"><mo> </mo><mi>Clifton</mi><mo> </mo><mi>beach</mi><mo> </mo><mi>contain</mi><mo> </mo><mi>common</mi><mo> </mo><mi>salt</mi><mo> </mo><mo>=</mo><mo> </mo><mn>60</mn><mo>.</mo><mn>75</mn><mo>%</mo><mo> </mo><mi>chlorine</mi><mo>.</mo><mo> </mo><mspace linebreak="newline"/><mn>100</mn><mo> </mo><mi mathvariant="normal">g</mi><mo> </mo><mo> </mo><mi>common</mi><mo> </mo><mi>salt</mi><mo> </mo><mo>=</mo><mo> </mo><mn>60</mn><mo>.</mo><mn>75</mn><mo>%</mo><mo> </mo><msub><mi>Cl</mi><mn>2</mn></msub><mspace linebreak="newline"/><mn>1</mn><mo> </mo><mi mathvariant="normal">g</mi><mo> </mo><mi>common</mi><mo> </mo><mi>salt</mi><mo> </mo><mo>=</mo><mo> </mo><mfrac><mrow><mn>60</mn><mo>.</mo><mn>75</mn></mrow><mn>100</mn></mfrac><mo>=</mo><mo> </mo><mn>0</mn><mo>.</mo><mn>6075</mn><mo> </mo><mi mathvariant="normal">g</mi></math>$ $<math xmlns="http://www.w3.org/1998/Math/MathML"><mn>6</mn><mo>.</mo><mn>40</mn><mo> </mo><mi mathvariant="normal">g</mi><mo> </mo><mi>NaCl</mi><mo> </mo><mi>from</mi><mo> </mo><mi>the</mi><mo> </mo><mi>Khewra</mi><mo> </mo><mi>mine</mi><mo> </mo><mo>=</mo><mo> </mo><mn>3</mn><mo>.</mo><mn>888</mn><mi mathvariant="normal">g</mi><mo> </mo><mi>of</mi><mo> </mo><msub><mi>Cl</mi><mn>2</mn></msub><mspace linebreak="newline"/><mn>1</mn><mo> </mo><mi mathvariant="normal">g</mi><mo> </mo><mi>of</mi><mo> </mo><mi>NaCl</mi><mo> </mo><mo>=</mo><mo> </mo><mfrac><mrow><mn>3</mn><mo>.</mo><mn>888</mn></mrow><mrow><mn>6</mn><mo>.</mo><mn>40</mn></mrow></mfrac><mo>=</mo><mn>0</mn><mo>.</mo><mn>06075</mn><mo> </mo><mi mathvariant="normal">g</mi></math>$ So, both the salt contain the same amount of chlorine. Hence, the law of constant is verified.
Hence, the correct answer is 3.

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