ad = √2 x √3= √6bc = √5 x √2= √10Hence ad < bc, and so ab<cd So, 25<23

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$Compare \frac{\sqrt{2}}{\sqrt{5}} and \frac{\sqrt{2}}{\sqrt{3}}$

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$\frac{\sqrt{2}}{\sqrt{5}} < \frac{\sqrt{2}}{\sqrt{3}}$

$\frac{\sqrt{2}}{\sqrt{5}} = \frac{\sqrt{2}}{\sqrt{3}}$

None of the above

$\frac{\sqrt{2}}{\sqrt{5}} > \frac{\sqrt{2}}{\sqrt{3}}$

answer is A.

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Detailed Solution

ad = √2 x √3

= √6

bc = √5 x √2

= √10

Hence ad < bc, and so

$\frac{a}{b} < \frac{c}{d} S o, \frac{\sqrt{2}}{\sqrt{5}} < \frac{\sqrt{2}}{\sqrt{3}}$

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