Complete combustion of 0.858 g of compound X, gives 2.63 g of CO2 and 1.28 g of H2O. The lowest molecular mass, X can have

molar mass of CO2 = 2.630 g or since the molar mass of CO2 is 44 g/molwe have 0.05976 moles of CO2 since there is 1 mole. so C in CO2we have 0.05976 moles of C or 0.718 g of Cmass of H2O = 1.280 g or since the molar mass of water is 18 g/molwe have 0.07105 moles of H2O, since there are 2 moles of H in 1 moles of H2O = 0.14210 moles of H or 0.143 g of H molar ratio C:H =0.05976 : 0.14210mass of C+H = 0.861 gor, after dividing by the smallest 0.05976molar ratio of C:H= 1.000 : 2.378multiply by 3 to get the whole number 3.000 : 7.134empirical formula is C3H7minimum molar mass is 43 g/mol

Complete combustion of 0.858 g of compound X, gives 2.63 g of CO2 and 1.28 g of H2O. The lowest molecular mass, X can have

molar mass of CO2 = 2.630 g or since the molar mass of CO2 is 44 g/molwe have 0.05976 moles of CO2 since there is 1 mole. so C in CO2we have 0.05976 moles of C or 0.718 g of Cmass of H2O = 1.280 g or since the molar mass of water is 18 g/molwe have 0.07105 moles of H2O, since there are 2 moles of H in 1 moles of H2O = 0.14210 moles of H or 0.143 g of H molar ratio C:H =0.05976 : 0.14210mass of C+H = 0.861 gor, after dividing by the smallest 0.05976molar ratio of C:H= 1.000 : 2.378multiply by 3 to get the whole number 3.000 : 7.134empirical formula is C3H7minimum molar mass is 43 g/mol

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Complete combustion of 0.858 g of compound X, gives 2.63 g of CO₂ and 1.28 g of H₂O. The lowest molecular mass, X can have

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43 g

86 g

129 g

172 g

answer is A.

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Detailed Solution

molar mass of CO₂ = 2.630 g or since the molar mass of CO₂ is 44 g/mol
we have 0.05976 moles of CO₂ since there is 1 mole. so C in CO₂
we have 0.05976 moles of C or 0.718 g of C
mass of H₂O = 1.280 g or since the molar mass of water is 18 g/mol
we have 0.07105 moles of H₂O, since there are 2 moles of H in 1 moles of H₂O = 0.14210 moles of H or 0.143 g of H molar ratio C:H =0.05976 : 0.14210
mass of C+H = 0.861 g
or, after dividing by the smallest 0.05976
molar ratio of C:H= 1.000 : 2.378
multiply by 3 to get the whole number 3.000 : 7.134
empirical formula is C₃H₇