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Q.

 Complete combustion of 0.86 gm of compound gives 2.64gm of  CO2 and 1.26gm of H2O . The empirical formula mass of compound is X. (compound do not contain oxygen). If empirical formula contains Y  no.of Carbon atoms and Z no.of  Hydrogen atoms then [X (Y+Z)] is 

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answer is 430.

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Detailed Solution

Moles of  CO2=2.6444=0.06      massofC=0.72
Moles of  H=2×MolesofH2O=2×1.2618=0.14
  mass of H = 0.14
Emp for  =C0.06H0.14=C3H7
  Emp formula mass = 43 
X = 43, Y = 3, Z = 7 So X (Y+Z) = 430                 
 

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