Complete combustion of 3 g of ethane gives x ×1022 molecules of water. The value of x is ___.(Round off to the Nearest Integer).[Use : NA=6.023×1023; Atomic masses in u :C:12.0,O:16.0;H=1.0]

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Complete combustion of $3 g$ of ethane gives $x$ $\times 10^{22}$ molecules of water. The value of $x$ is ___.(Round off to the Nearest Integer).

[Use : $N_{A} = 6.023 \times 10^{23}$ ; Atomic masses in $u$ $: C : 12.0, O : 16.0; H = 1.0]$

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answer is 18.

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Detailed Solution

$C_{2} H_{6} + O_{2} \to 2 {C O}_{2} + 3 H_{2} O 30 g m 3 N_{A} 3 g m ?$

$= 0.3 \times 6.023 \times 10^{23}$ molecules of $H_{2} O$

$= 1.8069 \times 10^{23}$

$= 18.069 \times 10^{22}$

Hence the correct answer is 18.

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